CSPP 50102 Mathematics for Computer Science—Summer 2011
Homework 2 (assigned June 29, due July 5)
Reading: Rosen chapter 4, sections 4.1–4.2.
Written assignment : Solve the following "Do" exercises and
assigned problems. Only solutions to the assigned problems should be
turned in. Note: You are responsible for the material covered in
both "Do" exercises and assigned problems.
"Do" Exercises (not to be handed in):
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Formulate and prove by mathematical induction a rule for the sums
12, 22 − 12,
32 − 22 + 12,
42 − 32 + 22 − 12,
52 − 42 + 32 − 22 + 12,
etc.
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Prove by induction that
n3 + (n + 1)3 + (n + 2)3
is divisible by 9 for all positive integers n.
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Prove by induction that if h > −1, then 1 + nh ≤
(1 + h)n for all nonnegative integers n.
This is called Bernoulli's inequality.
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Prove by induction that the following laws for positive exponents are valid,
where n and m are positive integers and a and b are
real numbers.
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(am)n = amn.
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(ab)n = anbn.
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A jigsaw puzzle is put together by successively joining pieces that fit together into
blocks. A move is made each time a piece is added to a block, or when two blocks are
joined. Use strong induction to prove that no matter how the moves are carried out,
exactly n − 1 moves are required to assemble a puzzle with n pieces.
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This problem considers exact L-tilings of a checkerboard. See Rosen, section 4.1, example
13, for definitions and terminology regarding tilings.
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Show that a 5 × 5 checkerboard with a 1 × 1 corner square removed has an exact
L-tiling.
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Find a 5 × 5 checkerboard with a 1 × 1 square removed that does not have an
exact L-tiling. Prove that an exact L-tiling does not exist for this board.
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Starting with 0, two players alternately add 1, 2, or 3 to a single running total. The
player who first brings the total to at least 1000 wins. Prove that the second player has
a strategy to win against any strategy for the first player. Hint: Use induction to prove
a more general statement.
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What is the flaw in the following proof?
Theorem. Let a be any positive number. For all positive integers n
we have an − 1 = 1.
Proof. By induction on n.
Base case: If n = 1, an − 1 =
a1 − 1 = a0 = 1.
Inductive step: By induction, assuming that the theorem is true for 1, 2, …,
n, we have
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a(n+1) − 1 = an =
an − 1 ×
an − 1/an − 2
= 1 × 1 / 1 = 1.
Therefore, the theorem is true for n + 1 as well.
Assigned problems (to be handed in):
Note: For full credit, proofs by mathematical induction must prove the base case, state
the inductive hypothesis, and justify main steps in the proof of the inductive step.
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Prove by induction the following summation formula:
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13 + 23 + … + n3 =
(1 + 2 + … + n)2. (5 points)
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Prove by induction that if n ≥ 10, then
2n > n3. (10 points)
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Use strong induction to prove that every positive integer n can be written as a sum
of distinct powers of 2, i.e., as a sum of a subset of the integers 20 = 1,
21 = 2, 22 = 4, etc. (5 points)
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The following proof by induction seems correct, but for some reason the equation
for n = 6 gives 1/2 + 1/6 + 1/12 + 1/20 + 1/30 = 5/6 on the left-hand side, and
3/2 − 1/6 = 4/3 on the right-hand side. Find the mistake. (10 points)
Theorem. For all positive integers n,
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1/(1 × 2) + 1/(2 × 3) + … + 1/((n − 1) × n) =
3/2 − 1/n.
Proof. By induction on n.
Base case: For n = 1, 3/2 − 1/n = 1/(1 × 2).
Inductive step: Assuming that the theorem is true for n,
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1/(1 × 2) + … + 1/((n − 1) × n) +
1/(n × (n + 1)) =
3/2 − 1/n + 1/(n × (n + 1))
= 3/2 − 1/n + [1/n − 1/(n + 1)]
= 3/2 − 1/(n + 1).
Therefore, the theorem is true for n + 1 as well.
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A tiling is a complete and exact covering of a region (usually planar) with multiple
copies of some smaller shape.
Suppose we are given L-shaped tiles, i.e., a 2 × 2 square tile with a missing
1 × 1 square. Prove that every region R of size
(2i) × (3j), where i and j are positive integers,
with no square missing has an exact L-tiling. (10 points)
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Recall the definition of a line map given in class:
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Define a line map as follows:
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A blank rectangle is a line map.
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A line map with a straight line drawn all the way across it is a new line map.
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Prove by induction on the number of lines that a line map with n distinct lines
has at least n + 1 regions. (5 points)
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Prove by induction on the number of lines that a line map with n distinct lines
has at most 2n regions. (5 points)
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Part (1) gives a lower bound on the number of regions in a line map. For example, a
line map with 5 lines must have at least 6 regions. Give an example of a line map that
achieves this lower bound, i.e., draw a line map with 5 lines and 6 regions.
(5 points)
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Part (2) says that a line map with 3 lines can have at most 8 regions. Can you draw a
line map with 3 lines that achieves this upper bound? Do so, or explain why you
cannot. (5 points)
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In this problem Hn denotes the nth harmonic number.
Modify the argument given in class proving
H2m ≥ 1 + m/2
(cf. Rosen, section 4.1, example 7) to prove that
H2m ≤ 1 + m for all m > 0.
(10 points)
Gerry Brady
Thursday June 30 02:56:29 CDT 2011