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Discrete Math, Second series, 2nd Problem Set (July 21)
REU 2003

Instructor: Laszlo Babai
Scribe: Mridul Mehta

Definition 0.1   A group is a set $ G$ with a binary operation $ G\times G \to G$ denoted by `$ \cdot$' or `$ +$' depending on context, satisfying:
  1. % latex2html id marker 1772
$ (\forall \; x, y \in G)(\exists! \; z \in G)(x \cdot y = z)$
  2. $ (\forall \; x, y, z \in G)((x\cdot y)\cdot z = x\cdot (y\cdot z))$
  3. % latex2html id marker 1776
$ (\exists \; 1_G)(\forall \; x \in G)(x \cdot 1_G = 1_G \cdot x = 1_G)$
  4. % latex2html id marker 1778
$ (\forall \; x \in G)(\exists \; x^{-1} \in G)(x\cdot x^{-1} = x^{-1} \cdot x = 1_G)$

Definition 0.2   We say that $ H \subseteq G$ is a subgroup of $ G$ (written $ H \le G$) if
  1. $ 1_G \in H$
  2. $ (\forall \; x, y \in H)(x\cdot y \in H)$
  3. $ (\forall \; x \in H)(x^{-1} \in H)$


\begin{exercise}
% latex2html id marker 826$G$\ has no subgroups other than $\...
...leftrightarrow $\ $\vert G\vert=1$\ or $\vert G\vert$\ is
prime.
\end{exercise}

Definition 0.3   The order of a group is the number of elements it contains, and is denoted $ \vert G\vert$.

Theorem 0.4 (Lagrange)   If $ G$ is finite and $ H \le G$, then $ \vert H\vert$ divides $ \vert G\vert$.

Remark 0.5   The union of two subgroups is in general, not a subgroup. (Consider $ 2{\mathbb{Z}}$ and $ 3{\mathbb{Z}}$ inside $ ({\mathbb{Z}}, +)$.)


\begin{exercise}
% latex2html id marker 831If $H, K \le G$, and $H\cup K \le G$, then $H\subseteq K$\ or $K\subseteq H$.
\end{exercise}


\begin{exercise}
Determine all (finite or infinite) groups for which the union any two of
subgroups is a subgroup.
\end{exercise}


\begin{exercise}
The intersection of any set of subgroups is a subgroup.
\end{exercise}

Definition 0.6   Subgroup generated by a subset $ S \subseteq G$ (written $ \langle S\rangle$). There are two equivalent definitions:
  1. $ \langle S\rangle \; = \bigcap\limits_{S\subseteq H\le G} H$
  2. % latex2html id marker 1819
$ \langle S\rangle \; = \left\{\textrm{ all products of generators and their inverses }\right\}$

Remark 0.7   By convention, we have $ \langle \emptyset\rangle \; = \{1\}$.


\begin{exercise}
% latex2html id marker 837Prove that the two definitions of $\langle S\rangle$\ are equivalent.
\end{exercise}

A graph is an object with a given set of vertices (usually denoted $ V$), which are connected by edges (denoted $ E$). We usually denote the graph by $ (V,E)$. A digraph is one in which the edges are directed (so that $ E \subseteq V\times V$).

A Cayley graph $ \Gamma$ of a group $ G$ with respect to a given set of generators $ S \subseteq G$ is the digraph $ \Gamma(G,S) = (G, E_S)$, where $ E_S = \{(g, sg)\colon g\in G, s\in S\}$.

Example 0.8   $ G = ({\mathbb{Z}}, +) = \; \langle 1\rangle$. The Cayley graph is:

% latex2html id marker 1578
\includegraphics[height=0.4in]{ints}

For example, $ (2,3) \in E$ because $ 2 + 1 = 3$ and $ 1 \in S$.

Definition 0.9   A group $ G$ is said to be cyclic if % latex2html id marker 1855
$ \exists \; a\in G$ such that $ G = \; \langle a\rangle$.

Definition 0.10   The order of an element $ x \in G$ (denoted by $ \ord(x)$) isdefined as the order of the cyclic subgroup generated by $ x$ i.e. $ \ord(x) =
\vert\langle x\rangle\vert$. (So $ \ord(x) = k \Rightarrow 1, x,
\ldots, x^{k-1}$ are distinct and $ x^k = 1$. Moreover, $ x^i = x^j
\Longleftrightarrow i\equiv j$ mod $ k$.)


\begin{exercise}
% latex2html id marker 840Suppose $G$\ is a {\bf abelian} gro...
...thop{\rm g.c.d.\,}\nolimits (a,b) = 1 \Rightarrow \ord(xy) = ab$.
\end{exercise}


\begin{exercise}
% latex2html id marker 843Suppose $G$\ is a abelian group. If...
...mid\,}\;\;
\mathop{\rm l.c.m.\,}\nolimits (a,b). \end{displaymath}\end{exercise}

The Dihedral group of order $ 2n$, denoted $ D_n$, is the group of symmetries (rotations and reflections) of the regular $ n$-gon in the plane.

Example 0.11   $ \vert D_3\vert = 6$ (group of symmetries of an equilateral triangle in the plane). If we denote the reflections by $ \tau_1, \tau_2, \tau_3$ and the rotations by $ 1, \rho, \rho^2$ ( $ \rho^3 = 1$), then $ D_3 = \langle \rho, \tau_1\rangle$. Consequently its Cayley graph is:

% latex2html id marker 1614
\includegraphics[height=2.5in]{s3cayley}

The edges comprising the triangles correspond to multiplication by $ \rho$ while the two-way arrows correspond to multiplication by $ \tau$ (since $ \tau$ has order 2). Following a directed edge in the opposite direction corresponds to multiplication by the inverse of the element. Each path corresponds to multiplying by the generators and/or their inverses in a particular order.

``Relation chasing'' Two different paths between the same pair of vertices give rise to two different expressions for the same group element as products of generators and their inverses. In particular, closed walks specify products of generators which equal the identity. Such products are called relations among the generators. For example, the inner triangle, from the identity to itself, shows the relation $ \rho^3 = 1$. The walk of length $ 2$ from $ 1$ to $ \tau$ to $ 1$ shows that $ \tau^2 = 1$. Traversing the bottom quadrilateral clockwise shows the relation $ \tau \rho \tau \rho = 1$. A more complex relation that is immediate from the diagram is $ \rho \tau \rho^2 \tau \rho = 1$.

Definition 0.12   A homomorphism from a group $ G$ to a group $ H$ is a map $ f:G \to H$ such that $ f(xy) = f(x)f(y)$ for all $ x, y \in G$.

Remark 0.13  
  1. $ f(1_G) = 1_H$.
  2. $ f(x^{-1}) = f(x)^{-1}$.
  3. $ f^{-1}(1_H) \le G$. The subgroup $ f^{-1}(1_H)$ is called the kernel of $ f$, denoted $ \ker(f)$.

For any $ g \in G$, ``conjugation by $ g$'' means a map $ G \to G$ given by $ x \mapsto g^{-1} x g =: x^g$. Note that $ \ker(f)$ is always closed under conjugation.

Definition 0.14   A subgroup $ N \le G$ is called a normal subgroup if it is closed under conjugation, i.e., $ (\forall \; g\in G)(N^g = N)$. We write $ N \triangleleft \;G$. (Here $ N^g = \{n^g\colon n\in N\}$.)

Definition 0.15   We say that a map $ f:G \to H$ is an isomorphism if $ f$ is a homomorphism that is both injective (one-to-one) and surjective (onto). We say $ G$ and $ H$ are isomorphic (notation: $ G \cong H$) if % latex2html id marker 1970
$ \exists f :G \to H$ isomorphism.

Definition 0.16   An automorphism of a group $ G$ is an isomorphism from $ G \to G$.


\begin{exercise}
% latex2html id marker 850Conjugation by any $g\in G$\ ($x \m...
...(induced by conjugation) are known
as {\bf inner automorphisms}.
\end{exercise}

The automorphisms of $ G$ form a group under composition, called Aut$ (G)$.

Example 0.17   Aut $ ({\mathbb{Z}}, +) \cong ({\mathbb{Z}}_2, +)$.


\begin{exercise}
% latex2html id marker 854Prove that $({\mathbb{Z}}^{\times}_...
...er's phi function) see Basic Number Theory
handout, Section 4.2.
\end{exercise}

Example 0.18   Aut $ ({\mathbb{Z}}_n, +) \cong ({\mathbb{Z}}^{\times}_{n}, \cdot\;)$.


\begin{exercise}
% latex2html id marker 859$\ord(k)$\ (in $({\mathbb{Z}}_n, +)$) $= \frac{n}{\mathop{\rm g.c.d.\,}\nolimits (k,n)}$.
\end{exercise}


\begin{exercise}
% latex2html id marker 863$\ord(g^k)$\ (in group $G$) $= \frac{\ord(g)}{\mathop{\rm g.c.d.\,}\nolimits (k, \ord(g))}$.
\end{exercise}


\begin{exx}
% latex2html id marker 866The group $({\mathbb{Z}}^{\times}_n, \cd...
...d prime $p$\ or
\item $n = 2p^k$\ for some odd prime $p$.
\end{itemize}\end{exx}

Definition 0.19   Direct Product. Given groups $ G$, $ H$, their Cartesian product $ G \times H = \{(g,h)\colon g\in G, h\in H\}$ is a group under componentwise multiplication.

Example 0.20   $ {\mathbb{Z}}_2 \times {\mathbb{Z}}_2 = \{1, a, b, c\}$, where $ a^2 = b^2 = c^2 = 1$, $ ab = c, ac = b, bc = a$, and the group is abelian. This is known as Klein's 4-group and is usually denoted by $ V_4$.


\begin{exercise}
% latex2html id marker 871Prove that ${\mathbb{Z}}^{\times}_8 \cong V_4$.
\end{exercise}


\begin{exercise}
% latex2html id marker 874The only groups (up to isomorphism) of order 4 are ${\mathbb{Z}}_4$\ and $V_4$.
\end{exercise}


\begin{exercise}
% latex2html id marker 877Find all $n$\ such that ${\mathbb{Z}}^{\times}_n \cong V_4$.
\end{exercise}

Definition 0.21   The center of a group $ G$, is defined to be $ Z(G) = \{a\in G\colon (\forall g\in G)(ga = ag)\}$.


\begin{exercise}
% latex2html id marker 880Find $Z(D_n)$.
\end{exercise}

We consider the map from % latex2html id marker 2008
$ G\to \textrm{Aut}(G)$ given by $ g\mapsto \{x\mapsto x^g\}$. This is a homomorphism of groups. The kernel of this map is $ Z(G)$. The image of this map is the group of inner automorphisms of $ G$, denoted by Inn$ (G)$.


\begin{exercise}
% latex2html id marker 882Prove that $G/Z(G) \cong \textrm{Inn}(G)$.
\end{exercise}


\begin{exercise}
% latex2html id marker 884Prove that $\textrm{Inn}(G)$\ is a normal subgroup of $\textrm{Aut}(G)$.
\end{exercise}

The quotient % latex2html id marker 2018
$ \textrm{Aut}(G)/\textrm{Inn}(G)$ is also denoted by % latex2html id marker 2020
$ \textrm{Out}(G)$, and referred to as the outer automorphism group of $ G$.

Definition 0.22   Symmetric group of degree $ \mathbf{n}$. This is the group of all permutations of a set of $ n$ elements under composition. It is usually denoted by $ S_n$. Clearly, $ \vert S_n\vert = n!$.

Remark 0.23   The group $ S_n$ has an important subgroup $ A_n$, known as the alternating group of degree $ n$ which consists of the even permutations of degree $ n$. For $ n \ge 2$, $ \vert A_n\vert = \frac{n!}{2}$.


\begin{exercise}
% latex2html id marker 886Prove that $Z(S_n) = \{1\}$\ for $n \ge 3$\ and $Z(A_n) = \{1\}$\ for $n \ge 4$.
\end{exercise}

Definition 0.24   Bipartite graph. The bipartite graph $ K_{p,q}$ is a graph with $ p+q$ vertices partitioned into two sets of $ p$ and $ q$ vertices respectively such that no two vertices in the same set are adjacent, while every pair of vertices not in the same set are adjacent.

Example 0.25   The bipartite graph $ K_{2,3}$ is:
% latex2html id marker 1754
\includegraphics[height=1.5in]{k23}


\begin{exercise}
% latex2html id marker 888Suppose $G = \;\langle S\rangle$, w...
...neq G)$. Prove that $\Gamma(G, S\cup S^{-1}) \nsupseteq K_{3,5}$.
\end{exercise}




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Varsha Dani 2003-08-04