next up previous
Next: Finite probability spaces. Up: Discrete Math, Second Series, Previous: Discrete Math, Second Series,

Revisit the first problem set

Definition 1.1   A product-free set in a group $ G$ is a subset $ L\subset G$ such that the equation $ xy=z$ has no solution in $ L$.
For a finite group $ G$, let $ \alpha(G)$ be the proportion of $ G$ in the largest product free set; $ \alpha(G)=\vert L\vert/\vert G\vert$, for $ L\subset G$ the largest product-free set.


\begin{exercise}
% latex2html id marker 812If $G\to H$\ is a surjective homomorphism, show that
$\alpha(G)\ge\alpha(H)$.
\end{exercise}


\begin{exercise}
% latex2html id marker 814
$\alpha(G)\le \frac12$.
\end{exercise}


\begin{exercise}
% latex2html id marker 816
If $G$\ has a subgroup of index $2$,...
...$G$\ is an
abelian groups of even order then $\alpha(G)=\frac12$.
\end{exercise}


\begin{exercise}
% latex2html id marker 818
If $G=K\times L$\ then $\alpha(G)=\max\{\alpha(K),\alpha(L)\}$.
\end{exercise}

Definition 1.2   A group is finitely generated if it has a finite set of generators.


\begin{exercise}
% latex2html id marker 820Find an infinite group $G$\ such th...
...e multiplicative group of complex numbers of unit
absolute value.
\end{exercise}


\begin{exercise}
% latex2html id marker 822Let $G$\ be an infinite abelian gro...
...is
a subgroup. ($H$\ is called the {\bf torsion subgroup} of $G$.
\end{exercise}

Theorem 1.3 (Fundamental theorem of finitely generated abelian groups)   Every finitely generated abelian group is the direct product of a finite number of cyclic groups. The number of infinite cycic groups in this factorization is unique. The product of the finite abelian subgroups in this factorization is unique; it is the torsion subgroup of $ G$.


\begin{exercise}
% latex2html id marker 824Let $G$\ be a finitely generated ab...
...oup $L$\ is not unique, unless
$G$\ is \lq\lq torsion-free'' ($T=\{1\}$\end{exercise}


\begin{exercise}
% latex2html id marker 826
Prove that $K\times L$\ is, the dire...
...roup is the direct product of cyclic groups of prime power
order.
\end{exercise}

Theorem 1.4 (Fundamental theorem of finite abelian groups)   Every finite abelian group is the direct product of cyclic groups of prime power order. The orders in this factorization are unique.


\begin{exercise}
Show that the subgroups in this factorization need not be
unique.
\end{exercise}

Thus to compute $ \alpha(G)$ for finite abelian groups, it suffices to know $ \alpha({\mathbb{Z}}_{p^k})$.

Corollary 1.5 (Fundamental theorem of finite abelian groups, Smith normal form)   Every finite abelian group is the direct product of cyclic groups $ {\mathbb{Z}}_{n_1}\times\dots{\mathbb{Z}}_{n_k}$ where $ 2\le n_1$ and $ n_{i-1}\mid n_i$ for all $ i$. The values $ n_1,\dots,n_k$ are unique.


\begin{exercise}
% latex2html id marker 833
$\alpha({\mathbb{Z}}_7)=2/7$, contrary
to the lower bound $\frac13$\ claimed in the first problem set.
\end{exercise}


\begin{exx}
% latex2html id marker 836
{\bf (Cauchy-Davenport)} For a prime $p$,...
...\in B\}$.
Then $\vert A+B\vert=\max\{p,\vert A\vert+\vert B\vert-1\}$.
\end{exx}


\begin{exercise}
% latex2html id marker 840
$\alpha({\mathbb{Z}}_p)=\lfloor\frac...
... the group.
Use the Cauchy-Davenport Theorem for the upper bound.
\end{exercise}


\begin{exercise}
% latex2html id marker 843
If $G$\ is abelian then $\frac27\le \alpha(G)\le\frac12$.
\end{exercise}


\begin{exercise}
% latex2html id marker 845
What is the exact value of
$\alpha({...
...\lq sum-free sets'' (abelian groups are comonly written
additively).
\end{exercise}

But the real question is for nonabelian groups. The most interesting cases would be classes of simple groups, starting with the alternating groups and the projective special linear groups.


\begin{exercise}
% latex2html id marker 848
If $H\lneq G$\ then $\alpha(G)\ge\frac{1}{[G:H]}$.
{\em Hint.} \ take a coset.
\end{exercise}


\begin{exercise}
% latex2html id marker 850
$\alpha(A_n)\ge\frac1n$. \end{exercise}

Conjecture 1.6   $ \alpha(A_n)=o(1)$ (i.e., $ \lim_{n\to\infty}\alpha(A_n)=0$.)

Nothing better than the inequalities $ 1/n\le \alpha(A_n)\le 1/2$ appears to be known for $ n\ge 5$. Perhaps $ \alpha(A_n)=1/n$ but the instructor would not bet on this one.

More generally, the $ o(1)$ is likely to hold for all finite simple groups:

Conjecture 1.7   Let $ G_n$ be an infinite sequence of finite simple groups ( $ \vert G_n\vert\to\infty$). Then $ \alpha(G_n)=o(1)$.

It would be of interest to prove this various inifinite classes of finite simple groups, such as the projective special linear groups.


next up previous
Next: Finite probability spaces. Up: Discrete Math, Second Series, Previous: Discrete Math, Second Series,
Varsha Dani 2003-08-04