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Subsections

Constructions: Undirected Graphs

To demonstrate that Corollary 1.5 completely describes the restrictions on the distance sequences of locally infinite vertex-transitive undirected graphs, we offer constructions for each distance sequence permitted. All graphs in this section are undirected.

$ 1,d,d,d,\dots $

For a vertex-transitive graph with the distance sequence $ \{f(k)\}$ such that $ f(k)=d$ for all $ k>1$ we need only consider an infinite tree of degree $ d$ .

$ 1,d,e$ % latex2html id marker 2059
$ (1\leq e\leq d)$

Define $ L(d,e)$ to be the complement of the union of $ d$ disjoint copies of the complete graphs $ K_{e+1}$ on $ e+1$ vertices. $ L(d,e)$ is vertex-transitive, has diameter 2, and distance sequence $ 1,d,e$ .

$ 1,d,\dots ,d,e$ % latex2html id marker 2076
$ (1\leq e\leq d)$

Let % latex2html id marker 2078
$ n\geq1$ be an integer, $ d$ an infinite cardinal, and % latex2html id marker 2082
$ 1\leq e\leq d$ . We now consider the case where the diameter is % latex2html id marker 2084
$ n\geq 3$ .

We construct a vertex-transitive graph $ G$ of degree $ d$ , diameter $ n$ and distance sequence $ f(k)=d$ % latex2html id marker 2094
$ (1\leq k\leq n-1)$ , $ f(n)=e$ . If $ a$ is a cardinal then we use $ [a]$ to denote a (standard) set of cardinality $ a$ .

Consider the graph $ G=C_{2n-4}\times L(d,e)$ where $ L(d,e)$ is the graph from Construction 3.2, $ C_{2n-4}$ is the $ (2n-4)$ -cycle, and $ \times$ refers to the Cartesian product. The Cartesian product $ G=H_1\times H_2$ of the graphs $ H_1$ and $ H_2$ is given by $ V(G)=V(H_1)\times V(H_2)$ , with $ (h_1,h_2)\sim(h_1^\prime,h_2^\prime)$ in $ G$ if either $ h_1=h_1^\prime$ and $ h_2\sim h_2^\prime$ , or $ h_2=h_2^\prime$ and $ h_1\sim h_1^\prime$ , where $ \sim$ refers to adjacency in the appropriate graph (cf.[B1, p. 1463]). Note that if $ H_1$ and $ H_2$ are vertex-transitive then so is $ G$ .

Note that $ L(d,e)$ is the complement of $ \overline{K_d}\times K_{e+1}$ , so $ V(L(d,e))=[d]\times [e+1]$ and $ V(G)=[2n-4]\times [d] \times [e+1]$ . There is an edge between $ (i,j,k)$ and $ (i',j',k')$ in $ G$ if either $ i=i'$ and % latex2html id marker 2158
$ j\neq j'$ , or % latex2html id marker 2160
$ i\equiv i'+1\mod(2n-4)$ , $ j=j'$ , and $ k=k'$ .

$ G$ has degree $ d$ , so its distance sequence begins with $ 1,d,\ldots ,d$ . Considering some vertex $ v=(i,j,k)$ , we see that the sphere $ S(t,v)$ is the set of vertices $ w=(i',j',k')$ for which one of the following holds:

  1. % latex2html id marker 2178
$ t\leq n-2$ , $ i'=i\pm t\mod (2n-4),\textrm{ }j'=j, \textrm{ and } k'=k;$
  2. % latex2html id marker 2182
$ 1\leq t\leq n-1$ , % latex2html id marker 2184
$ i'=i\pm (t-1)\mod (2n-4) \textrm{ and } j'\neq j;$
  3. % latex2html id marker 2186
$ 2\leq t\leq n$ , % latex2html id marker 2188
$ i'=i\pm (t-2)\mod (2n-4), j'=j, \textrm{ and } k'\neq k.$

So $ S(n,v)$ is the set of vertices described by condition (3), and $ \lvert S(n,v) \rvert =f(n)=e$ .


next up previous
Next: Constructions: Directed Graphs Up: Distance Sequences in Locally Previous: The Proofs
2005-03-08