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Constructions: Directed Graphs

Theorem 4.1   Let $ \{d(k)\}$ be any nonincreasing sequence of infinite cardinals. Then $ 1,d(1),d(2),\dots $ is the out-distance sequence of some vertex-transitive digraph. Furthermore, let $ n>0$ and let $ \{{g^{+}}(k)\}$ be the out-distance sequence of some vertex-transitive digraph of finite out-degree. Then

$\displaystyle 1,d(1),\dots,d(n),{g^{+}}(n+1),{g^{+}}(n+2),\dots$

is the out-distance sequence of some vertex-transitive digraph.

In particular then, Theorem 4.1 implies that the out-distance sequences of vertex-transitive digraphs with infinite out-degree are not always unimodal. Theorem 4.1 follows from the following constructions.

$ 1,d,\dots ,d$ and $ 1,d,d,\dots $

Let $ d$ be an infinite cardinal, and let $ n>0$ . We construct $ G_{n,d}$ , which has the vertex set $ \mathbb{Z}\times[d]$ . There is an edge from $ (z_1,\alpha_1)$ to $ (z_2,\alpha_2)$ in $ G_{n,d}$ when $ z_2-z_1=1$ or $ z_2-z_1>n$ . So $ G_{n,d}$ is acyclic and has out-distance sequence $ \{{g^{+}}(k)\}$ satisfying $ {g^{+}}(k)=d$ for all % latex2html id marker 2239
$ 0<k\leq n$ , and $ {g^{+}}(n+1)=0$ .

We also define $ G_{\infty,d}$ on the same vertex set. There is an edge from $ (z_1,\alpha_1)$ to $ (z_2,\alpha_2)$ in $ G_{\infty,d}$ if and only if $ z_2-z_1=1$ . Thus $ G_{\infty,d}$ has out-distance sequence $ 1,d,d,\dots $ .

$ 1,d(1),d(2),\dots $

Definition 4.2   Let $ G_1$ and $ G_2$ be digraphs with vertex sets $ V_1$ and $ V_2$ , respectively. Then the lexicographic product $ G_1\bullet G_2$ (cf.[B1, p. 1463]) has vertex set $ V_1\times V_2$ ; there is an edge from the vertex $ (v_1,v_2)$ to the vertex $ (v^{\prime}_1,v^{\prime}_2)$ in $ G_1\bullet G_2$ when either $ (v_1,v^{\prime}_1)$ is an edge in $ G_1$ , or $ v_1=v^{\prime}_1$ and $ (v_2,v^{\prime}_2)$ is an edge in $ G_2$ . On more than two graphs, we define the product recursively: $ G_1\bullet \cdots\bullet G_n=(G_1\bullet \cdots\bullet G_{n-1})\bullet G_n$ . (This product is associative.)

Note that if $ G$ and $ H$ are vertex-transitive, $ G\bullet H$ is vertex-transitive.

Observation 4.3   If $ G$ and $ H$ are acyclic, $ G\bullet H$ is acyclic.

Observation 4.4   Let $ \{d(k)\}$ be a nonincreasing sequence of infinite cardinals. Let $ G_1$ be a vertex-transitive digraph with out-distance sequence $ 1,d(1),\dots,d(m)$ , and let $ G_2$ be a vertex-transitive digraph with % latex2html id marker 2325
$ \lvert V(G_2) \rvert \leq d(m)$ and with out-distance sequence $ 1,{g^{+}}(1),{g^{+}}(2),\dots$ . If $ G_1$ is acyclic, then $ G_1\bullet G_2$ has out-distance sequence

$\displaystyle 1,d(1),\dots,d(m),{g^{+}}(m+1),{g^{+}}(m+2),\dots.$

Let $ \{d(k)\}$ be a nonincreasing sequence of infinite cardinals; so the sequence must be eventually constant. Thus there exists an $ m$ such that $ d(i)=d(m)$ for all % latex2html id marker 2341
$ i\geq m$ . Then by Observations 4.3 and 4.4,

$\displaystyle (G_{1,d(1)}\bullet \cdots \bullet G_{m,d(m)})\bullet G_{\infty,d(m+1)}$

(with $ G_{n,d}$ as constructed in 4.1) is vertex-transitive and has out-distance sequence $ 1,d(1),d(2),\dots $ . This proves the first part of Theorem 4.1.

$ 1,d(1),\dots ,d(n),{g^{+}}(n+1),{g^{+}}(n+2),\dots $

Let $ \{d(k)\}$ as above and let $ G$ be a vertex-transitive digraph of finite out-degree with out-distance sequence $ \{{g^{+}}(k)\}$ . From Observations 4.3 and 4.4, then,

$\displaystyle (G_{1,d(1)}\bullet G_{2,d(2)} \bullet \cdots \bullet G_{n,d(n)})\bullet G$

is a vertex-transitive digraph with out-distance sequence

$\displaystyle 1,d(1),\dots,d(n),{g^{+}}(n+1),{g^{+}}(n+2),\dots.$

This proves the second part of Theorem 4.1.% latex2html id marker 2361
$ \qedsymbol$


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Next: The Locally Finite Case Up: Distance Sequences in Locally Previous: Constructions: Undirected Graphs
2005-03-08