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Extremal Set Theory

Theorem 0.10 (Dijen K. Ray-Chaudhuri, Richard M. Wilson)   Let $ A_1,\dots,A_m\subseteq\{1,\dots,n\}$ be a set system satisfying
  1. uniformity, i.e. $ \vert A_i\vert=k$ for every $ i$,
  2. $ s$ sizes of intersections, i.e. $ \vert A_i\cap
A_j\vert\in\{\ell_1,\dots,\ell_s\}$ for every $ i\neq j$.
Then $ m\leq \binom{n}{s}$.


\begin{exercise}
% latex2html id marker 858In class we proved that $m\leq
\bin...
....)
Prove the same bound on $m$\ without assumption \ref{it:unif}.
\end{exercise}

Remark 0.11   For non-uniform set systems the above bound is tight. Simply take all sets of size at most $ s$.


\begin{exercise}
% latex2html id marker 860
[R-W Theorem]
Under assumptions \ref...
... (products of at most $s-1$\ variables)
are linearly independent.
\end{exercise}

Remark 0.12   The original proofs were more involved and considered matrices of size $ \binom{n}{s}\times\binom{n}{s}$. The matrix $ M=(m_{i,j})_{m\times n}$, where $ m_{i,j}=1$ if $ j\in A_i$ and 0 otherwise, is called an incidence matrix of $ A_1,\dots,A_m$.

Ray-Chaudhuri and Wilson used so-called higher incidence matrices for their proof.

Definition 0.13   Inclusion Matrices. The $ s$-inclusion matrix of the set system $ A_1,\dots,A_m\subset
[n]$ (where $ [n]=\{1,\dots, n\}$) is an $ m\times {n\choose s}$ matrix $ M_s=(m_{i,j}^{(s)})$ is defined as follows: $ i$ ranges from $ 1$ to $ m$, $ j$ ranges through the subsets of $ [n]$ of size $ s$, and $ m_{i,j}^{(s)}=1$ if $ j\subseteq A_i$, and 0 otherwise.

Ray-Chaudhuri and Wilson proved that $ M_s$ has full row rank, i.e. % latex2html id marker 1682
$ \mathop{\rm rk}\nolimits (M_s)=m$, by showing that $ M_sM_s^t$ is a non-singular matrix.


\begin{exercise}
% latex2html id marker 863Prove: the $(i,j)$-entry of $M_sM_s...
...m{\vert A_i\cap A_j\vert}{s}.\end{displaymath}($1\le i,j \le m.$)
\end{exercise}


next up previous
Next: About this document ... Up: Discrete Math, Fifth Problem Previous: An Extremal Problem in
Varsha Dani 2003-07-25